题目

Given a list of N student records with name, ID and grade. You are supposed to sort the records with respect to the grade in non-increasing order, and output those student records of which the grades are in a given interval.

Input Specification:

Each input file contains one test case. Each case is given in the following format:

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N
name[1] ID[1] grade[1]
name[2] ID[2] grade[2]
... ...
name[N] ID[N] grade[N]
grade1 grade2

where name[i] and ID[i] are strings of no more than 10 characters with no space, grade[i] is an integer in [0, 100], grade1 and grade2 are the boundaries of the grade’s interval. It is guaranteed that all the grades are distinct.

Output Specification:

For each test case you should output the student records of which the grades are in the given interval [grade1, grade2] and are in non-increasing order. Each student record occupies a line with the student’s name and ID, separated by one space. If there is no student’s grade in that interval, output NONE instead.

Sample Input 1:

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Tom CS000001 59
Joe Math990112 89
Mike CS991301 100
Mary EE990830 95
60 100

Sample Output 1:

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Mike CS991301
Mary EE990830
Joe Math990112

Sample Input 2:

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2
Jean AA980920 60
Ann CS01 80
90 95

Sample Output 2:

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NONE

题解

思路

  • 读数据
  • 排序
  • 输出
  • 完事儿嗷

数据结构

  • students 存放所有的学生，是一个列表
  • 一个student用一个三项列表表示
    • 第一项是名字
    • 第二项是科目
    • 第三项是成绩
  • low,high 是成绩上下限

算法

  • 读入students数据
  • 读入成绩的上下限
  • 将students按照上下限清理一下
  • 如果students为空，输出NONE
  • 否则，将students排序并输出

代码

  • 由于使用Python能AC，因此只放了Python解。
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num, students = int(input()), []
for _ in range(num):
    students.append(input().split())
low, high = list(map(int, input().split()))
students = [i for i in students if low <= int(i[2]) <= high]
if len(students) == 0:
    print("NONE")
else:
    students.sort(key=lambda x: int(x[2]), reverse=True)
    for student in students:
        print(student[0], student[1])